54 lines
1.1 KiB
Markdown
54 lines
1.1 KiB
Markdown
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% This is generated by ESQL's AbstractFunctionTestCase. Do no edit it. See ../README.md for how to regenerate it.
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**Examples**
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This example returns the first three characters of every last name:
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```esql
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FROM employees
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| KEEP last_name
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| EVAL ln_sub = SUBSTRING(last_name, 1, 3)
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```
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| last_name:keyword | ln_sub:keyword |
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| --- | --- |
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| Awdeh | Awd |
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| Azuma | Azu |
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| Baek | Bae |
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| Bamford | Bam |
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| Bernatsky | Ber |
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A negative start position is interpreted as being relative to the end of the string. This example returns the last three characters of of every last name:
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```esql
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FROM employees
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| KEEP last_name
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| EVAL ln_sub = SUBSTRING(last_name, -3, 3)
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```
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| last_name:keyword | ln_sub:keyword |
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| --- | --- |
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| Awdeh | deh |
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| Azuma | uma |
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| Baek | aek |
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| Bamford | ord |
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| Bernatsky | sky |
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If length is omitted, substring returns the remainder of the string. This example returns all characters except for the first:
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```esql
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FROM employees
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| KEEP last_name
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| EVAL ln_sub = SUBSTRING(last_name, 2)
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```
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| last_name:keyword | ln_sub:keyword |
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| --- | --- |
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| Awdeh | wdeh |
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| Azuma | zuma |
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| Baek | aek |
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| Bamford | amford |
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| Bernatsky | ernatsky |
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