Invoke make as $(MAKE) from within makefiles
Our makefiles require gnumake. Under some unices, gnumake is installed as gmake, with plain "make" referring to a something less featureful. So it's necessary to invoke make as $(MAKE) from within makefiles, in order to make sure we invoke the same variant.
This commit is contained in:
parent
fde61026f7
commit
07ecf11d15
2
Makefile
2
Makefile
|
|
@ -151,7 +151,7 @@ srcdist: distclean
|
|||
rm -rf $(TARGET_SRC_DIR)
|
||||
|
||||
distclean: clean
|
||||
make -C $(AMQP_CODEGEN_DIR) distclean
|
||||
$(MAKE) -C $(AMQP_CODEGEN_DIR) distclean
|
||||
rm -rf dist
|
||||
find . -regex '.*\(~\|#\|\.swp\|\.dump\)' -exec rm {} \;
|
||||
|
||||
|
|
|
|||
|
|
@ -4,10 +4,10 @@ TARGET_DIR=rabbitmq_server-$(VERSION)
|
|||
TARGET_TARBALL=rabbitmq-server-generic-unix-$(VERSION)
|
||||
|
||||
dist:
|
||||
make -C ../.. VERSION=$(VERSION) srcdist
|
||||
$(MAKE) -C ../.. VERSION=$(VERSION) srcdist
|
||||
tar -zxvf ../../dist/$(SOURCE_DIR).tar.gz
|
||||
|
||||
make -C $(SOURCE_DIR) \
|
||||
$(MAKE) -C $(SOURCE_DIR) \
|
||||
TARGET_DIR=`pwd`/$(TARGET_DIR) \
|
||||
SBIN_DIR=`pwd`/$(TARGET_DIR)/sbin \
|
||||
MAN_DIR=`pwd`/$(TARGET_DIR)/share/man \
|
||||
|
|
|
|||
|
|
@ -4,9 +4,9 @@ TARGET_DIR=rabbitmq_server-$(VERSION)
|
|||
TARGET_ZIP=rabbitmq-server-windows-$(VERSION)
|
||||
|
||||
dist:
|
||||
make -C ../.. VERSION=$(VERSION) srcdist
|
||||
$(MAKE) -C ../.. VERSION=$(VERSION) srcdist
|
||||
tar -zxvf ../../dist/$(SOURCE_DIR).tar.gz
|
||||
make -C $(SOURCE_DIR)
|
||||
$(MAKE) -C $(SOURCE_DIR)
|
||||
|
||||
mkdir $(SOURCE_DIR)/sbin
|
||||
mv $(SOURCE_DIR)/scripts/rabbitmq-server.bat $(SOURCE_DIR)/sbin
|
||||
|
|
|
|||
Loading…
Reference in New Issue